+0  
 
0
47
3
avatar+50 

Robert and Caleb each had a collection of rocks. Caleb had 2/9 as many rocks as Robert. When Robert lost 40 rocks, Caleb then had twice as many as Robert. How many rocks were in Robert's collection at first?

 May 14, 2021
 #1
avatar+1899 
0

C = 2/9R

C = 2(R-40)

2/9R = 2(R-40)

 

Take it from there. :))

 

=^._.^=

 May 14, 2021
 #2
avatar+50 
0

Is the answer 45?

Foaltohors  May 14, 2021
 #3
avatar+1899 
0

2/9R = 2(R-40)

2/9R = 2R - 80

80 = 16/9R

R = 45

yayyy :))

 

=^._.^=

catmg  May 14, 2021

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