In triangle ABC, AB=15, BC=20, and AC=25. Find the length of the shortest altitude in this triangle.
This is a right triangle
Area = (1/2) (15) (20) = 150
The shortest altitude is drawn to the longest side
Area = (1/2) (25) (altitude)
150 = (1/2) (25) (altitude)
300 = 25 * altitude
300 / 25 = 12 = altitude
+32 
