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The isosceles triangle and the square shown here have the same area in square units. What is the height of the triangle, $h$, in terms of the side length of the square, $s$?

 Mar 27, 2020
 #2
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Mmmmm...this is an interesting one

 

If s =   the  side of the square

 

So its area = s^2

 

And  s  also  = the base of  the isosceles triangle

 

So....the  area of the  isosceles  triangle  =   (1/2) base  * h   =  (1/2) s * h

 

And  this  =  the area of the square

 

Therefore

 

(1/2) s * h  =  s^2         divide  through by  s

 

(1/2) h  =  s                multiply through by 2

 

h =  2S

 

 

cool cool cool

 Mar 27, 2020

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