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# Hellpp (Circle Theorems)

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Need Hellp

Nov 29, 2018
edited by Guest  Nov 29, 2018
edited by shook  Nov 29, 2018

#1
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DCO....since CO = DO.....the angles opposite those sides are equal

So DCO = x

CBO....angle OBQ = 90°  [tangent meeting a radius forms a right angle ]

So CBO = 90 - 2x

OCB   .......since OB = OC, the angles opposite those sides are equal

So OCB = CBO =  90 - 2x

BCD = DCO + OCB =  (x) + ( 90 - 2x) =  ( 90 - x)   [angle addition postulate ]

DOB is a central angle that is twice the measure of BCD = 2(90 - x) = 180 - 2x  = measure of minor arc   DB   [ a central angle measures twice  an inscribed angle intercepting the same arc ]

Note that arc DCB = 360° - minor arc DB  =  360 - (180 - 2x) = 180 + 2x

[ the sum of arcs in acircle = 360° ]

Angle  y  =  (1/2) [ difference of  arc DCB - arc DOB]

[ The angle formed by the intersection of 2 tangents, 2 secants or 1 tangent and 1 secant outside the circle equals half the difference of the intercepted arcs ]

(1/2) [ (180 + 2x) - (180 - 2x) ]  =

(1/2) [  2x + 2x ]  =

(1/2) [ 4x]  =

2x

Nov 29, 2018
#2
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I only got 2/6 i need proof that links to circle theorums

shook  Dec 5, 2018