We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

https://vle.mathswatch.co.uk/images/questions/question15502.pngpleasehelp VERY HARD HELP

AsadRehman Nov 16, 2017

#1**-1 **

The Pythagoras's theorem is leg^2 +leg^2 = hyp^2

squares are two right triangles

since we know a square is 5 on both sides, we can do

5^2 + 5^2 = hyp^2

25 +25 = hyp ^2

50 = hyp ^2

sq root of 50 = hyp

so the diagonal of the square is sq root of 50, and the sides are 5.

since the sq root of 50 is smaller than 9, and 5 is smaller than 9, we have proven that the square can fit in the circle

Guest Nov 16, 2017

#2**-1 **

The largest square that will fit inside the circle will have a side, S, of

4.5^2 + 4.5^2 = S^2 simplify

2 *4.5^2 = S^2

√[ 4.5^2 * 2 ] = S^2 take the square root

√4.5^2 √ 2 = s

4.5√2 = S ≈ 6.36 cm so...a square with a side of 5 will fit inside the circle.......

CPhill 3 hours ago

Guest Nov 16, 2017