https://vle.mathswatch.co.uk/images/questions/question15502.pngpleasehelp VERY HARD HELP

AsadRehman
Nov 16, 2017

#1**-1 **

The Pythagoras's theorem is leg^2 +leg^2 = hyp^2

squares are two right triangles

since we know a square is 5 on both sides, we can do

5^2 + 5^2 = hyp^2

25 +25 = hyp ^2

50 = hyp ^2

sq root of 50 = hyp

so the diagonal of the square is sq root of 50, and the sides are 5.

since the sq root of 50 is smaller than 9, and 5 is smaller than 9, we have proven that the square can fit in the circle

Guest Nov 16, 2017

#2**-1 **

The largest square that will fit inside the circle will have a side, S, of

4.5^2 + 4.5^2 = S^2 simplify

2 *4.5^2 = S^2

√[ 4.5^2 * 2 ] = S^2 take the square root

√4.5^2 √ 2 = s

4.5√2 = S ≈ 6.36 cm so...a square with a side of 5 will fit inside the circle.......

CPhill 3 hours ago

Guest Nov 16, 2017