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In triangle $ABC,$ $\cos A = \frac{2}{3}$ and $\cos B = \frac{2}{5}.$  Given that the perimeter of triangle $ABC$ is $24$, compute the area of triangle $ABC.$

 Jan 4, 2024
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cool cool cool                           

.
 Jan 5, 2024
edited by CPhill  Jan 5, 2024

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