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Find the smallest integer n > 15 such that n = 15 (mod 77) and n = 15 (mod 286).

 Dec 5, 2019
 #1
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n mod 77 =15

n mod 286 =15

 

The LCM(77, 286) = 2002

The smallest n > 15 is:

 

2002m + 15, where m=0, 1, 2, 3.......etc.

n =2002 * 1 + 15 =2017 - the smallest n

 Dec 5, 2019

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