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I cant figure out the answer

 Feb 28, 2019
 #1
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This is just a substitution question.

 

\(x_{n+1}=(x_n)^2-x_n\\ so\\ x_{2}=(x_1)^2-x_1\\ If \;\; x_1=1\\ then\; x_{2}=(1)^2-1=0\\ \)

 

You can do the others yourself!

 Feb 28, 2019

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