In right triangle \(ABC\) with \(\angle B = 90^\circ\), we have \(2\sin A = 3\cos A\). What is \(\tan A\)?
This is very simialr to another of your posts....did you look at the way it was solved?
2 sin a = 3 cos a divide both sides by 2 and cos a
sin a /cos a = 3/2
tan a = 3/2