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In right triangle \(ABC\) with \(\angle B = 90^\circ\), we have \(2\sin A = 3\cos A\). What is \(\tan A\)?

 Jun 28, 2019
 #1
avatar+18439 
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This is very simialr to another of your posts....did you look at the way it was solved?

 

2 sin a = 3 cos a    divide both sides by 2   and cos a

sin a /cos a = 3/2

tan a = 3/2

 Jun 28, 2019

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