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1. The hypotenuse of a right triangle measures 2sqr15 centimeters and its shorter leg measures 2sqr6 centimeters. What is the measure of the larger acute angle of the triangle? Round your answer to the nearest tenth of a degree.

 Feb 12, 2020
edited by Fexli  Feb 12, 2020
 #1
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No  number of centimeters  displays  (for me, anyway  )

 

cool cool  cool

 Feb 12, 2020
 #2
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Sorry! I fixed it

Fexli  Feb 12, 2020
 #3
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OK

2sqrt (15)  = sqrt (60)

2sqrt (6)  = sqrt (24)

 

The  other leg  =    sqrt  [ (sqrt (60))^2  - (sqrt (24))^2 ]  = sqrt  [ 60 - 24 ]  = sqrt (36)  = 6= the longer leg

 

The larger angle [call it A ] is opposite the longer leg....so we can use the tangent to find this angle

 

tan A =  6 / sqrt (24)      and using the tangent inverse to find  A

 

arctan (6/ sqrt (24)) = A   ≈  50.8°

 

 

cool cool cool

CPhill  Feb 12, 2020

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