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A box contains six cards. Three of the cards are black on both sides, one card is black on one side and red on the other, and two of the cards are red on both sides. You pick a card uniformly at random from the box and look at a random side. Given that the side you see is red, what is the probability that the other side is red? Express your answer as a common fraction.

Logic  Nov 26, 2018
 #1
avatar+3197 
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deleted

Rom  Nov 26, 2018
edited by Rom  Nov 26, 2018
 #2
avatar+92808 
+1

Here's my take on this

 

P ( Red l Red )   =    P ( Red and Red )

                                _______________

                                     P (Red)

 

We can disregard the three Black / Black cards  [ since we already  hold a Red ]

 

Of the three remaining cards, we had (2/3) of a chance of choosing a Red/Red card

 

And of the three remaining cards, we had a 5/6 chance of  choosing a "Red" side showing first

 

So......the probability is

 

(2/3) / (5/6)   =   (2/3) (6/5)  = 12 / 15   =   4 / 5

 

 

cool cool cool

CPhill  Nov 26, 2018
edited by CPhill  Nov 26, 2018

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