+0  
 
0
49
3
avatar+418 

\(\binom{4}{0}+\binom{5}{1}+\binom{6}{2}+\binom{7}{3}.\)

Logic  Oct 16, 2018
 #1
avatar+93866 
+1

ARe they meant to be binomial coefficients or vectors or what?

Melody  Oct 16, 2018
 #2
avatar+418 
+1

Binomial Coefficients...

Logic  Oct 16, 2018
 #3
avatar+93866 
+1

Then just do it with a calculator.

 

Most calc have an    \(^nC_r\)     button

 

the first one is just

 

\(4\;^nC_r\;0+ etc\\ \text{Anyway you should know that }^nC_r\;0 =1\)

 

On the web 2 calc just write in

 

nCr(4,0) +       etc

Melody  Oct 16, 2018

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