Points \(P\) and \(R\) are located at (1, 3) and (7, 15) respectively. Point \(M\) is the midpoint of segment \(PR\). Segment \(PR\) is reflected over the \(x\)-axis. What is the sum of the coordinates of the image of point \(M\)(the midpoint of the reflected segment)?

Logic Jun 8, 2019

#1**+3 **

point M = midpoint of segment PR = \(\Big( \frac{1+7}{2},\frac{3+15}{2}\Big)\ =\ \Big( \frac{8}{2},\frac{18}{2}\Big)\) = (4, 9)

To reflect segment PR over the x-axis, we make the y-coordinate of each of its points negative. So...

image of point M = (4, -9)

sum of the coordinates of the image of point M = 4 + -9 = -5

Here's a graph: https://www.desmos.com/calculator/bmiffafl6d

hectictar Jun 8, 2019

#1**+3 **

Best Answer

point M = midpoint of segment PR = \(\Big( \frac{1+7}{2},\frac{3+15}{2}\Big)\ =\ \Big( \frac{8}{2},\frac{18}{2}\Big)\) = (4, 9)

To reflect segment PR over the x-axis, we make the y-coordinate of each of its points negative. So...

image of point M = (4, -9)

sum of the coordinates of the image of point M = 4 + -9 = -5

Here's a graph: https://www.desmos.com/calculator/bmiffafl6d

hectictar Jun 8, 2019