1. if 8^x = 27, then what is 4^(2x-3)?
if 8^x = 27, then what is 4^(2x-3)?
Hello Leaded!
\(x=\frac{log(27)}{log(8)}\)
\(4^{2x-3}=4^{2\cdot \frac{log(27)}{log(8)}-3}=\color{blue}1.265625=1+\frac{17}{64}\)
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