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Suppose we have a bag with 10 slips of paper in it. Eight of these have a 2 on them and the other two have a 4 on them.

What is the expected value of the number shown when we draw a single slip of paper?

 Nov 24, 2018

Best Answer 

 #2
avatar+1200 
+2

I appreciate the help but your answer was wrong. here is the answer

 

Expected value is computed by multiplying all of the possible outcomes by their probabilities, and then summing. \(8/10\) of the time we draw a 2 and \(2/10\) of the time we draw a 4. Therefore the expected value is

 

\(2\cdot\frac{8}{10} + 4\cdot\frac{2}{10} = \frac{12}{5}.\)

 Nov 24, 2018
 #1
avatar+6196 
+2

\(P[2]=\dfrac{8}{10}=\dfrac{4}{5}\\ P[4] = \dfrac 1 5\\ E[N] = 8\cdot 2 \cdot \dfrac 4 5 + 2 \cdot 4 \cdot \dfrac 1 5 = \\ \dfrac{64}{5} + \dfrac 8 5 = \dfrac{72}{5}\)

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 Nov 24, 2018
 #2
avatar+1200 
+2
Best Answer

I appreciate the help but your answer was wrong. here is the answer

 

Expected value is computed by multiplying all of the possible outcomes by their probabilities, and then summing. \(8/10\) of the time we draw a 2 and \(2/10\) of the time we draw a 4. Therefore the expected value is

 

\(2\cdot\frac{8}{10} + 4\cdot\frac{2}{10} = \frac{12}{5}.\)

Logic Nov 24, 2018

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