+0  
 
+1
439
1
avatar+544 

https://vle.mathswatch.co.uk/images/questions/question1265.png

really need help

please like if hard questionblush

don't think anyone can answer this???crying

prize for who answers this: i will like all your posts.smiley

ask CPhill i liked his posts.

lynx7  Nov 18, 2017

Best Answer 

 #1
avatar+7154 
+3

 

volume of water removed in 30 minutes  =  2m * 1m * 20cm

volume of water removed in 30 minutes  =  2m * 1m * 0.2m

volume of water removed in 30 minutes  =  0.4 m3

 

So the pump removes water at a rate of  0.4 m3  per  30 minutes.

That is  0.8 m3  per hour.

 

volume of pond  =  area of trapezoid base     *   height

volume of pond  =  (1.4m + 0.6m) / 2  *  2m   *   1m

volume of pond  =   2 m3

 

2 m3 / 0.8 m3  =  2.5 

 

So he has to wait  2.5  hours total for the pond to completely empty.

That is  60 + 60 + 30 minutes,  or  150 minutes .

hectictar  Nov 18, 2017
 #1
avatar+7154 
+3
Best Answer

 

volume of water removed in 30 minutes  =  2m * 1m * 20cm

volume of water removed in 30 minutes  =  2m * 1m * 0.2m

volume of water removed in 30 minutes  =  0.4 m3

 

So the pump removes water at a rate of  0.4 m3  per  30 minutes.

That is  0.8 m3  per hour.

 

volume of pond  =  area of trapezoid base     *   height

volume of pond  =  (1.4m + 0.6m) / 2  *  2m   *   1m

volume of pond  =   2 m3

 

2 m3 / 0.8 m3  =  2.5 

 

So he has to wait  2.5  hours total for the pond to completely empty.

That is  60 + 60 + 30 minutes,  or  150 minutes .

hectictar  Nov 18, 2017

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