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prize for who answers this: i will like all your posts.surprise

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lynx7  Nov 25, 2017

Best Answer 

 #1
avatar+91253 
+3

 

 

\(\angle ODC=\angle OBC=90^\circ\qquad \) A tangent is at right angles to the radius that it intersects with

\(\angle BOD=2*\angle BFD \)               

             When subtended from the same arc (BC), the angle at the  centre = 2* the angle at the circumference

\(\therefore \angle BOD=2*76=152^\circ\)

\(152+90+90+\angle BCD=360 \qquad \text{Angle sum of quadrilateral}\\ 332+\angle BCD=360 \\ \angle BCD=28^\circ\)

Melody  Nov 25, 2017
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1+0 Answers

 #1
avatar+91253 
+3
Best Answer

 

 

\(\angle ODC=\angle OBC=90^\circ\qquad \) A tangent is at right angles to the radius that it intersects with

\(\angle BOD=2*\angle BFD \)               

             When subtended from the same arc (BC), the angle at the  centre = 2* the angle at the circumference

\(\therefore \angle BOD=2*76=152^\circ\)

\(152+90+90+\angle BCD=360 \qquad \text{Angle sum of quadrilateral}\\ 332+\angle BCD=360 \\ \angle BCD=28^\circ\)

Melody  Nov 25, 2017

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