#1**0 **

a)

Distance is 195 miles.

Speed or rate is 50 mph

1) Use the distance formula.

d=rt; where d=distance, r=rate or speed, t=time

You have d and r, solve for t.

195=50t

t=195/50=3.9 hours

2) Tack on that time to the time it leaves.

Leaves at 3:30

Add the whole amount of hours (3)

Becomes 6:30

Turn the 0.9 hours to minutes by multiplying by 60

0.9*60=54 minutes

Add 54 minutes to 6:30, you get the arrival time which is:

7:24

b) Since the coach has a lower average speed in other words, it's slower, the arrival time will be later than the calculated time of 7:24.

ChowMein Jun 13, 2018