+0  
 
-1
51
7
avatar+-65 

If x is an integer that 9>x>2, what is the greatest value of 5x+11?

 Apr 14, 2021
 #1
avatar+180 
0

If x is an integer that 9>x>2, what is the greatest value of 5x+11?

 

Well we want to find the biggest value of x in this inequality which is 8.

 

Then, we plug in the eight to 5x+11 which will become 5(8) + 11

 

= 40 + 11 = 51

 

smiley

 Apr 14, 2021
 #3
avatar
-2

Ok, so what is: The product of three consecutive integers is 990. What is their sum?

Guest Apr 14, 2021
 #4
avatar+180 
+1

Ok, so what is: The product of three consecutive integers is 990. What is their sum?

 

The product of the three consecutive integers is 990

 

990= 9x10x11

 

So the answer is 30.

Mathdory  Apr 14, 2021
 #5
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-1

yeah, but what is: How many of the smallest, non-overlapping triangular regions are there in Figure 4 of the sequence whose first three figures are shown?

 

Guest Apr 14, 2021
 #2
avatar+28 
+1

So basically you want to make x as large as possible, which is 8, and plugging in the values gets you 5(8)+11, which simplifies to 40+11=51. 

 Apr 14, 2021
 #6
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-1

yeah, but what is .......... indecision

 

(im a different guest btw)

 Apr 14, 2021

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