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What value of \(x\) will give the maximum value for \(-x^2- 6x + 12\)?

 Jul 30, 2019
 #1
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+1

This is a dome shaped parabola  (negative leading x^2 coefficient)

max will be at  -b/2a      ....do you think you can find that?

 Jul 30, 2019
 #2
avatar+106536 
+1

-1x^2 - 6x  + 12

 

This is a parbola that turns downward......the x value that maximizes this  is just the x coordinate of the vertex  =

 

- b / [2a]  =  - (-6)  / ( 2 * -1)   =  6 / -2  =  - 3

 

Verified here : https://www.desmos.com/calculator/6ae5cmoa4o

 

 

cool cool cool

 Jul 30, 2019

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