+-649 You have linear functions $p(x)$ and $q(x)$. You know $p(2)=3$, and $p(q(x))=4x-7$ for all $x$. Find $q(-1)$.
Help, I don't know what to do here!
+1 p(x)=\(\frac{3}{2}\) because p(2)=3.
So, \( \frac{3q(x)}{2}\)=4x-7.
multiply both sides by 2/3
q(x)=\(\frac{8x-14}{3}\)
substitute -1 for x
-8-14 = -22
so the answer is \(\frac{-22}{3}\)
+175 This answer is wildly incorrect. A constant function cannot return two different values.
