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Find the roots of x^2+12x+36 +25=0

Note: The roots are not necessarily real.

 Jan 25, 2019
 #1
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x^2 + 12x + 36 + 25 = 0

 

(x^2 + 12x + 36) + 25 = 0

 

(x + 6)^2 + 25 =  0

 

( x + 6)^2 =  -25       take both roots

 

x + 6   =   ±√(-25)

 

x + 6  =  ±5i

 

x = -6 + 5i      or  x =   -6 - 5i

 

 

cool cool cool

 Jan 26, 2019

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