+0  
 
0
149
1
avatar+169 

A line segment begins at (2, 5). It is 10 units long and ends at the point (-6, y) where $y > 0. What is the value of y?

 Jun 27, 2018

Best Answer 

 #1
avatar+7352 
+2

By the distance formula...

 

distance between  (2, 5)  and  (-6, y)   =   \(\sqrt{(-6-2)^2+(y-5)^2}\)

 

The problem tells us that the distance between  (2, 5)  and  (-6, y)  is  10 units, so.....

 

\(\sqrt{(-6-2)^2+(y-5)^2}=10\)

                                                          Square both sides of the equation.

(-6 - 2)2 + (y - 5)2  =  100

                                                          Multiply out each exponent on the left side.

( -8 )2 + (y - 5)(y - 5)  =  100

 

64 + y2 - 10y + 25  =  100

                                                          Combine  64  and  25  to get  89

y2 - 10y + 89  =  100

                                                          Subtract  100  from both sides of the equation.

y2 - 10y - 11  =  0

                                                          Factor the left side.

(y - 11)(y + 1)  =  0

                                                          Set each factor equal to zero and solve for  y .

y - 11  =   0       or       y + 1  =  0

   y  =  11                      y  =  -1

 

Since  y > 0  ,  the solution must be  y = 11   smiley

 Jun 27, 2018
 #1
avatar+7352 
+2
Best Answer

By the distance formula...

 

distance between  (2, 5)  and  (-6, y)   =   \(\sqrt{(-6-2)^2+(y-5)^2}\)

 

The problem tells us that the distance between  (2, 5)  and  (-6, y)  is  10 units, so.....

 

\(\sqrt{(-6-2)^2+(y-5)^2}=10\)

                                                          Square both sides of the equation.

(-6 - 2)2 + (y - 5)2  =  100

                                                          Multiply out each exponent on the left side.

( -8 )2 + (y - 5)(y - 5)  =  100

 

64 + y2 - 10y + 25  =  100

                                                          Combine  64  and  25  to get  89

y2 - 10y + 89  =  100

                                                          Subtract  100  from both sides of the equation.

y2 - 10y - 11  =  0

                                                          Factor the left side.

(y - 11)(y + 1)  =  0

                                                          Set each factor equal to zero and solve for  y .

y - 11  =   0       or       y + 1  =  0

   y  =  11                      y  =  -1

 

Since  y > 0  ,  the solution must be  y = 11   smiley

hectictar Jun 27, 2018

29 Online Users

avatar
avatar
avatar