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Find the value of n that satisfies 2(n + 1)! + 6n! = 3(n + 1), where n! = n * (n - 1) * (n - 2) *** 2 * 1.

matth99  Aug 12, 2018
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2(n + 1)! + 6n! = 3(n + 1), If the RHS is meant to be: 3(n + 1)!, then there is a solution for n = 5. Otherwise, there is no "integer" solution for n. There could be a solution if by (n + 1)! you mean the "Gamma Function"!!!

Guest Aug 12, 2018

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