The set S = {1,2,3,...,49,50} contains the first 50 positive integers. After the multiples of 2 and the multiples of 3 are removed, how many integers remain in the set S?

matth99
Aug 27, 2018

#1**+2 **

All multiples of 2 =50 / 2 = 25

All multiples of 3 that are odd =50/2 =16/2 =8

All multiples of 2 + All multiples of 3 that are odd

25 + 8 =33. Therefore, the remaining numbers in the set are:

50 - 33 = 17 - Numbers remain in the set.

[1, 5, 7, 11, 13, 17, 19, 23, 25, 29, 31, 35, 37, 41, 43, 47, 49]

Guest Aug 28, 2018