+0

Maths help needed urgently

0
271
7

https://vle.mathswatch.co.uk/images/questions/question15829.png

What is the answer to the question on the link please?

Got to give homework back tomorrow

Dec 12, 2018

#1
+2

Ok....we have this

924  =  4 ( x + 1) (x + 11)     divide both sides by 4

231  = (x + 1) (x + 11)      simplify

231 =   x^2 + 12x + 11     subtract  231 from both sides

x^2 + 12x - 220  = 0       factor as

(x + 22) ( x - 10) = 0

Set both factors to 0  and solve for x and we get that

x =  -22    (reject)     or    x  = 10  (accept)

Dimensions of cuboid  are

4, (10 +1), (10 + 11)  =

4, 11, 21   Dec 12, 2018
#2
0

Thanks, i checked the answer but still got 5/7 marks. Do you know what elese i need to add?

This is my working:

924  =  4 ( x + 1) (x + 11)
231  = (x + 1) (x + 11)
231 =   x^2 + 12x + 11
x^2 + 12x - 220  = 0
(x + 22) ( x - 10) = 0

x=10 x=-22

4, (10 +1), (10 + 11)=
4,11,21

Guest Dec 12, 2018
#4
+1

Man, I don't know....this seems pretty complete, to me....

I don't know what else they are looking for....   CPhill  Dec 12, 2018
#7
0

The answer is complete

PartialMathematician  Dec 13, 2018
#3
0

https://vle.mathswatch.co.uk/images/questions/question15829.png

What is the answer to the question on the link please?

Got to give homework back tomorrow.

So far, this is my working:

924  =  4 ( x + 1) (x + 11)
231  = (x + 1) (x + 11)
231 =   x^2 + 12x + 11
x^2 + 12x - 220  = 0
(x + 22) ( x - 10) = 0

x=10 x=-22

4, (10 +1), (10 + 11)=
4,11,21

… but I still only get 5/7 marks

Do you know what else i need to add?

Dec 12, 2018
#6
0

Did you attempt the problem before and get it wrong? if you did, (I know the website you are on ) then even if you get it right the next time, it will only give 5/7, not 7/7. If you attempt two times and get those attempts wrong, but get the third attempt correct, then you score 3/7 points. This process continues al the way until 1/7.

- PM

Dec 13, 2018