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https://vle.mathswatch.co.uk/images/questions/question18404.png

 Mar 24, 2020
 #1
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0

CPHILL plz help

 Mar 24, 2020
 #2
avatar+1970 
+1

Sorry I'm not CPhill... but here.

 

Since we know supplementary angles and vertical angles, we can solve this easily.

 

Angle BCD=20 degrees

Angle CDA=115 degrees.

 

That means Angle CBA is also 115 degrees, which makes this shape a kite.

 

Hope this helped!

 Mar 24, 2020
 #3
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thank you so much

Guest Mar 24, 2020
 #4
avatar+1970 
+1

Anytime :D

CalTheGreat  Mar 24, 2020
 #5
avatar+111330 
+1

Here's away to prove  this

 

Connect BD

 

Since  AB  =AD.....then in triangle DAB angles ADB  and ABD  are  equal =  [180 - 110]/2  =

70/2 =  35°

 

So angle CDB  =180  -65 - 35 =  80°

 

And  angle BCD  = 20°

 

So...in triangle CDB  angle CBD  =   180  - 80 - 20  = 180 - 100  = 80°

 

But....in triangle  CDB,angles  CBD  are equal

 

So....this means that  CB = CD

 

But  since  CB = CD   and AB = AD....then ABCD is a kite  because it has two pairs of equal adjacent sides

 

 

cool cool cool

 Mar 24, 2020

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