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 Mar 24, 2020

Best Answer 

 #1
avatar+23710 
+2

the first three terms are found by substituting   n = 1      n= 2     and n = 3 into the equation

n2 + 20    put in  n = 1     1^2 + 20 = 21

   I think you can do the  n=2  and n=3 versions

 

 

How many terms are less than 50?

n^2 + 20  < 50

n^2  <   30

n   <  5.47   ( taking the positive root only)  

                         the answer would be 5                  5^2 + 20 = 45                but 6 would not work  6^2 + 20 = 56

 Mar 24, 2020
 #1
avatar+23710 
+2
Best Answer

the first three terms are found by substituting   n = 1      n= 2     and n = 3 into the equation

n2 + 20    put in  n = 1     1^2 + 20 = 21

   I think you can do the  n=2  and n=3 versions

 

 

How many terms are less than 50?

n^2 + 20  < 50

n^2  <   30

n   <  5.47   ( taking the positive root only)  

                         the answer would be 5                  5^2 + 20 = 45                but 6 would not work  6^2 + 20 = 56

ElectricPavlov Mar 24, 2020

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