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mathswatch.co.uk/images/questions/question15868.png

 Mar 21, 2020
 #1
avatar+111321 
0

URL  not found  ????

 

 

cool cool cool

 Mar 21, 2020
 #2
avatar+1956 
+2

This can't be found... when you get it to work, I will be happy to help!

 Mar 21, 2020
 #3
avatar
0

https://vle.mathswatch.co.uk/images/questions/question15868.png

plz help urgent

 Mar 21, 2020
 #4
avatar+1956 
+1

Hint:

 

Since the radius is 28mm, we know that the diameter is 56mm.

 

Therefore, the length of the rectangle will be 56mm. Knowing this, I bet you can work out the area of the rectangle :D

 

Hope this helped!

 Mar 21, 2020
 #5
avatar
0

i got 117mmsquared as the answer its wrong what did you get

Guest Mar 21, 2020
 #6
avatar+111321 
+1

If we connect the  centers  of  the circles, we will have  an equilateral triangle  with sides of  2R = 2(28) =    56mm

 

The  height  of this triangle, H,   can be found as

 

tan 60°  = H  /(1/2 side length of the triangle)

√3 = H  / 28

28√3  =  H

 

Then the  height  of  the rectangles  =  R  + height  of triangle  + R  =   2R + 28√3  =  2R + 28√3  = 56 + 28√3

 

And the  width of the  rectangle  = 4R  = 4*28  = 112

 

So....the area  of the  rectangle  = 

 

(56 + 28√3) (112)  ≈   

 

11703.711  mm^2  ≈  11700 mm^2

 

 

 

cool cool cool

 Mar 21, 2020

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