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A cone-shaped glass and a tin can are filled with water.   

The height of the cone is 12" (12 inches) and it has a radius of 1.5" (1½ inches).   

The can is 2 inches high and has a diameter of 4 inches.   

Which container holds more water?  How much more water does the larger container hold?  Use 3.14 for π, and remember to use the correct units in your answer. 

Show all your work.   

 Jan 31, 2019

Best Answer 

 #1
avatar+27470 
+4

Volume of a cone = {1/3)*pi*(r^2)*h  where r = radius (1.5" here), h = height (12" here)

 

Volume of tin can = pi*(R^2)*H   where R = radius (2"), and H = height (2")

 

Can you take it from here?

 Jan 31, 2019
 #1
avatar+27470 
+4
Best Answer

Volume of a cone = {1/3)*pi*(r^2)*h  where r = radius (1.5" here), h = height (12" here)

 

Volume of tin can = pi*(R^2)*H   where R = radius (2"), and H = height (2")

 

Can you take it from here?

Alan Jan 31, 2019
 #2
avatar+26 
+2

Yes thank you

BellaNight7310  Jan 31, 2019

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