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What is the value of $n$ such that $\(10^n = 10^{-5}\times \sqrt{\frac{10^{73}}{0.001}}$?\)

 Apr 3, 2020
 #1
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Recognize that 0.001 is \(10^{-3}\).

 

\(\sqrt{10^{76}}\)=\(10^{38}\).

 

Thus, \(10^n=10^{-5}*10^{38}=10^{33}. \)

 

n = 33.

 Apr 3, 2020

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