+0  
 
0
48
2
avatar

https://vle.mathswatch.co.uk/images/questions/question16113.png

https://vle.mathswatch.co.uk/images/questions/question17778.png

 May 1, 2020
 #1
avatar+111329 
+1

For the first one we need to find the  probability of a "3"

 

This is    1 -  ( .13 +.05 + .21 + .19 + .3)    = .12

 

P (3 or 4)   =  [ .12 + .21]  =   .33

 

If rolled 300 times  we would expect a 3 or 4    =   300 (.33)  =   99 times

 

cool cool cool

 May 1, 2020
 #2
avatar+111329 
+1

The second is easy....

 

If she has a 20% chance of winning she bought   60 (.20)  =  12 tickets

 

cool cool cool

 May 1, 2020

7 Online Users

avatar
avatar