The lengths of two opposite sides of a square are decreased by $40\%$ while the lengths of the other two sides are increased by $50\%$ to form a rectangle. By what percent does the square's area decrease?

helpppp Mar 28, 2020

#2**0 **

So the original area of the square is \(x^2\) and after the increase, it is \(0.6x*1.5x\), which equals \(0.9x^2\). Dividing the two areas, you see there is a 10% decrease.

Guest Mar 28, 2020

#3**0 **

So the original area of the square is \(x^2\) and after the increase, it is \(0.6x*1.5x\), which equals \(0.9x^2\). Dividing the two areas, you see there is a 10% decrease.

Guest Mar 28, 2020

#4**+2 **

So the original area of the square is \(x^2\) and after the increase, it is \(0.6x*1.5x\), which equals \(0.9x^2\). Dividing the two areas, you see there is a 10% decrease.

P.S. Sorry about the extra guest answers, my browser was glitching out.

MathIsCool Mar 28, 2020