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The lengths of two opposite sides of a square are decreased by $40\%$ while the lengths of the other two sides are increased by $50\%$ to form a rectangle. By what percent does the square's area decrease?

 Mar 28, 2020
 #2
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So the original area of the square is \(x^2\) and after the increase, it is \(0.6x*1.5x\), which equals \(0.9x^2\). Dividing the two areas, you see there is a 10% decrease. 

 Mar 28, 2020
 #3
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So the original area of the square is \(x^2\) and after the increase, it is \(0.6x*1.5x\), which equals \(0.9x^2\). Dividing the two areas, you see there is a 10% decrease. 

 Mar 28, 2020
 #4
avatar+22 
+2

So the original area of the square is \(x^2\) and after the increase, it is \(0.6x*1.5x\), which equals \(0.9x^2\). Dividing the two areas, you see there is a 10% decrease. 

 

P.S. Sorry about the extra guest answers, my browser was glitching out. 

 Mar 28, 2020
 #5
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+1

Excellent, MathisCool  !!!!

 

 

cool cool cool

CPhill  Mar 28, 2020

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