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In the figure, \($\overline{DC}$ \)is parallel to\( $\overline{AB}$.\) We have \($\angle DCA = 40^\circ$ \)and \($\angle ABC = 73^\circ$\). Find $\angle ACB$.

 Apr 5, 2020
 #1
avatar+631 
+1

A _____________________B

 

 

 

D _________________C

 

By alternate interior angles, DCA = CAB. All angles in a triangle add up to 180. Can you solve it?

 Apr 5, 2020
 #3
avatar+631 
0

How did you get that number?


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