If no one shares an office, in how many ways can 3 people be assigned to 5 different offices? (Each person gets exactly one office).
do not give answer i want to be able to do some of the math if do give answer at least give an good explanation
We have 5 offices and we want to choose any 3 of them....so
C(5,3) = 10 ways to do this
This is the same as taking any set of three elements from 5 = 10 sets
Is it P(5,3)=60 ways.
Ah....thanks, tertre....I forgot that we need to consider the people as well as the offices.....thanks for the correct answer !!!!
No problem.......! I also often feel confused about whether to use the which one....