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# permuatations cphill help

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If no one shares an office, in how many ways can 3 people be assigned to 5 different offices? (Each person gets exactly one office).

do not give answer i want to be able to do some of the math if  do give answer at least give an good explanation

Apr 1, 2020

#5
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Is it P(5,3)=60 ways.

Apr 1, 2020

#1
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We  have  5 offices  and  we  want  to  choose any 3 of them....so

C(5,3)  =  10  ways  to do this

This is the  same  as  taking any set  of  three elements  from 5 =  10 sets

Apr 1, 2020
#5
+4569
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Is it P(5,3)=60 ways.

tertre Apr 1, 2020
#6
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Ah....thanks, tertre....I forgot  that  we  need to consider  the people as well as the  offices.....thanks for the correct answer  !!!!

CPhill  Apr 1, 2020
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People are unique! Don't forget that CPhill .

#9
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No problem.......!  I also often feel confused about whether to use the which one....

tertre  Apr 1, 2020
#10
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Yeah.......I realized  that  when I saw tertre's answer......

CPhill  Apr 1, 2020
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