+0

# permutations

-4
71
6
+-291

Given three members of a group -- Alice, Bob, and Carol -- in how many ways can these three be chosen to be the three officers (president, secretary, and treasurer) of the group, assuming no person holds more than one job?

Apr 1, 2020

#1
+4569
+1

Alice, Bob, Carol:

3 ways to choose the person for the first job, then two ways, and finally one way.

3 * 2 * 1 = 6 ways.

Apr 1, 2020
#2
+626
+1

If alice goes first

Alice can be 3 choices

Bob can have 2 choices

Carol can have 1 choice

In other words, it's just 3!

Apr 1, 2020
#4
+320
+1

um... what. So Alice can have 3 choices, bob has 2, and carol has 1. That means its 6 ways..... so it's not just 3...

AnimalMaster  Apr 1, 2020
#5
+626
+1

I do not understand what you are confused on. 3! means 3 * 2 * 1. Also, you cannot apply factorial to other problems like this (I just used it to represent my answer).

#6
+320
+1

Ohhh, I'm so sorry! I thought you put an exclamation mark after the 3. Not 3 factorial.

AnimalMaster  Apr 1, 2020