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Semicircle ADB with diameter 6 is rotated 60∘ anticlockwise at the point A to form another semicircle AEC with diameter AC. Find the area of the shaded region.

 

 Jun 28, 2020
 #1
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B makes a 60 out of 360o   cicular area of radius 6

60/360  x   pi  6^2    add to this the shaded semicirle area  then subtract the unshaded semi circle area and you are left with

60/360  x  pi   x  6^2   units^2 

 Jun 28, 2020

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