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1) https://vle.mathswatch.co.uk/images/questions/question15501.png

2)https://vle.mathswatch.co.uk/images/questions/question2821.png

thank you !!

 Mar 24, 2020
 #1
avatar+111330 
+1

(1)

 

Notice that the  greatest  "dimension"  of the square  will be its  diagonal length

 

This is given  by

 

√ [ side^2 + side^2 ]   =  √[7^2 + 7^2 ] =  √[98]  ≈   9.9 cm

 

So....since  the diameter of the circle is 11 cm, the squre will fit easily inside the circle

 

 

 

cool cool cool

 Mar 24, 2020
 #2
avatar+111330 
+1

(2)   Here...we're using  the  distance formula  in 3D

 

We have  that

 

HB  = √ [ BA^2  + AD^2  + DH^2]

 

Note  that  AD = BC  and AE = HD

 

So

 

25  =  √ [ 10^2  +  8^2  +  AE^2]     simplify

 

25   =√ [ 100 + 64  + AE^2 ]      

 

25  =√ [ 164  + AE^2]      square both sides

 

225 =  164  + AE^2

 

225 - 164  = AE^2

 

61 =  AE^2      take the positive square root

 

AE  = √61 ≈  7.81  cm

 

 

 

cool cool cool

 Mar 24, 2020

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