+0  
 
0
66
3
avatar

https://vle.mathswatch.co.uk/images/questions/question17709.png

https://vle.mathswatch.co.uk/images/questions/question16708.png

https://vle.mathswatch.co.uk/images/questions/question15992.png

 May 2, 2020
 #1
avatar+111433 
+1

First one

 

M    :     W     :    C

17          9         12

 

Let  the number of women  =  x

So.....the  number of men  = x + 3512

 

And we know that

 

W             9

___  =    ____

M             17

 

 

So this implies that

 

9             x

__  =  ________        cross-multiply

17      x + 3512

 

9 ( x + 3512) = 17x     simplify

 

9x + 31608  = 17 x        subtract  9x from both sides

 

31608  =  8x       divide both sides by 8

 

3951  = x  = the number of women

 

We also know  that

 

 C           12         4

___  =    ___  =  __

 W            9         3

 

So  multiplying both sides of this  by W  we have that

 

C  = (4/3)W

 

C = (4/3)3951   = 5268  =   number of children

 

 

cool cool cool

 May 2, 2020
 #2
avatar+111433 
+1

Second one.....this one is a little  difficult  !!!

 

Note  that  the ratio of 2  to 7   is the same as   6 to 21

 

So the ratio of blue to green  =  6 : 21

 

And  red : green  =  1 : 3   =    7 : 21

 

So.....we have the following possibilities

 

B      R      G          Total

6      7       21          34

12   14      42          68

24   28      84        136

 

So....the greatest number of red sweets possible   =   24

 

 

cool cool cool

 May 2, 2020
 #3
avatar+111433 
+1

Last one

 

Circle : Stalls

    2   :    5

 

5/2  = S/C

(5/2)C  =  S

 

So  the  number that can possiblt occupy S  = (5/2)(528)  = 1320

But only 2/3 of these showed up  = 880

 

So  the %   of  occupancy  =    [ 528 + 880 ]  / [528 + 1320]   = 1408 / 1848  = .76  = 76%

 

 

cool cool cool 

 May 2, 2020

18 Online Users

avatar
avatar