+0  
 
0
48
3
avatar+61 

Find all real numbers x such that 3x-7<5x+9 in interval notation                                                                                                        THE LESS THAN SIGN IS LESS THAN EQUAL TO

Leaded  Nov 16, 2018
edited by Leaded  Nov 16, 2018
edited by Leaded  Nov 16, 2018
 #1
avatar+92785 
+1

3x-7  ≤   5x+9   subtract  5x from both sides

 

-2x  - 7  ≤  9      add 7 to both sides

 

-2x  ≤  16       

Divide both sides by -2  and reverse the inequality sign [ since we are dividing an inequality by a negative  ] 

 

x ≥  -8

 

 

cool cool cool

CPhill  Nov 16, 2018
 #2
avatar+422 
0

If it's in interval notation, wouldn't it be \([-8, \infty)\) ?

CoolStuffYT  Nov 16, 2018
 #3
avatar+92785 
0

Correct!!!!....I forgot  about the interval notation.......!!!!

 

 

cool cool cool

CPhill  Nov 16, 2018
edited by CPhill  Nov 16, 2018

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