Problem 1: Let \[f(x) = \frac{3x - 7}{x + 1}.\]Find the domain of $f$. Give your answer using interval notation.

Problem 2:Let $f(x) = 3(x - 6)^2 + 1$. What is the range of $f$? Express your answer with interval notation.

kk345 Mar 2, 2019

#1**+1 **

\(f(x) = \frac{3x - 7}{x + 1}.\)

The domain is all values of x that don't make the denominator = 0

Thus x = - 1 is excluded from the domain

So....the domain is ( - inf, -1) U (-, inf )

\(f(x) = 3(x - 6)^2 + 1\)

This is a parbola that opens upward with a vertex of (6, 1)

So....the range is [ 1, inf )

CPhill Mar 2, 2019