We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

Problem 1: Let \[f(x) = \frac{3x - 7}{x + 1}.\]Find the domain of $f$. Give your answer using interval notation.

Problem 2:Let $f(x) = 3(x - 6)^2 + 1$. What is the range of $f$? Express your answer with interval notation.

kk345 Mar 2, 2019

#1**+1 **

\(f(x) = \frac{3x - 7}{x + 1}.\)

The domain is all values of x that don't make the denominator = 0

Thus x = - 1 is excluded from the domain

So....the domain is ( - inf, -1) U (-, inf )

\(f(x) = 3(x - 6)^2 + 1\)

This is a parbola that opens upward with a vertex of (6, 1)

So....the range is [ 1, inf )

CPhill Mar 2, 2019