Two men stand back-to-back and walk in opposite directions for $40$ yards each. Each of them then turns left and walks another $40$ yards each. In yards, how far are the two men from one another?

The0neXWZ Sep 9, 2023

#1**+1 **

*Two men stand back-to-back and walk in opposite directions for $40$ yards each. Each of them then turns left and walks another $40$ yards each. In yards, how far are the two men from one another?*

square root of 80^{2} + 80^{2} = sqrt(12,800) = **113.14 yards**

Draw it. Remember, the men's lefts are opposite directions.

The men are 80 yds north & south

and another 80 yds east & west.

Just imagine that it's a big box, and solve for the diagonal.

edited to add: I calculated the diagonal by using the Pythagorean Theorem.

Since it's a big square, we could have multiplied a side by the square root of 2.

_{.}

Bosco Sep 10, 2023

#1**+1 **

Best Answer

*Two men stand back-to-back and walk in opposite directions for $40$ yards each. Each of them then turns left and walks another $40$ yards each. In yards, how far are the two men from one another?*

square root of 80^{2} + 80^{2} = sqrt(12,800) = **113.14 yards**

Draw it. Remember, the men's lefts are opposite directions.

The men are 80 yds north & south

and another 80 yds east & west.

Just imagine that it's a big box, and solve for the diagonal.

edited to add: I calculated the diagonal by using the Pythagorean Theorem.

Since it's a big square, we could have multiplied a side by the square root of 2.

_{.}

Bosco Sep 10, 2023