Two men stand back-to-back and walk in opposite directions for $40$ yards each. Each of them then turns left and walks another $40$ yards each. In yards, how far are the two men from one another?
Two men stand back-to-back and walk in opposite directions for $40$ yards each. Each of them then turns left and walks another $40$ yards each. In yards, how far are the two men from one another?
square root of 802 + 802 = sqrt(12,800) = 113.14 yards
Draw it. Remember, the men's lefts are opposite directions.
The men are 80 yds north & south
and another 80 yds east & west.
Just imagine that it's a big box, and solve for the diagonal.
edited to add: I calculated the diagonal by using the Pythagorean Theorem.
Since it's a big square, we could have multiplied a side by the square root of 2.
.
Two men stand back-to-back and walk in opposite directions for $40$ yards each. Each of them then turns left and walks another $40$ yards each. In yards, how far are the two men from one another?
square root of 802 + 802 = sqrt(12,800) = 113.14 yards
Draw it. Remember, the men's lefts are opposite directions.
The men are 80 yds north & south
and another 80 yds east & west.
Just imagine that it's a big box, and solve for the diagonal.
edited to add: I calculated the diagonal by using the Pythagorean Theorem.
Since it's a big square, we could have multiplied a side by the square root of 2.
.