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# Question on use of calculator

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I'm doing some work on trigonometriy but I can't do sin y on my calc, its just sin and when I do sin y = 8/12 on this websites calculator it doesn't show anything! So may I ask how an I supposed to do this?

https://vle.mathswatch.co.uk/images/questions/question9828.png

May 2, 2020

#1
+111433
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No prob, TacoBell

We just need to  realize  how to find angle  x

However.....we  don't need the sine here.......the sine is the opposite / hypotenuse

But we  actually have    opp / adj   =  tangent

So  we need

tan x   =  8/12    to  find  this angle we need to  take the arctangent   [ also called the inverse tangent]

I don't know how it might be noted on your calculator......most  use  tan-1

[ Make sure your calculator is in degree mode  !!!]

So  we have

tan -1  ( 8/12)  =  x

33.69°   =  x    =    33.7° [ to one decimal place ]

Remember that to find an angle, we need to use the inverse functions  ]

Let me know if you have any problems here

May 2, 2020
edited by CPhill  May 2, 2020
#2
+30689
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In order to get the web2.0calc calculator to solve sin y = 8/12 you have to type sin(y) = 8/12 and then press enter (note the brackets around y). This is the outcome:

May 2, 2020
#3
+30689
+2

Just looked at the question, and of course, it should be tan(y) = 8/12.  However, the same principle applies.

Alan  May 2, 2020
edited by Alan  May 2, 2020