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winkwinkwink

lynx7  Apr 1, 2018
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+2

We can find angle BCA  in the large triangle thusly :

 

sin BCA / 5.6  =  sin 50  / 9.3

 

sin BCA  =  5.6sin 50  / 9.3

 

So

 

arcsin (5.6 sin 50 / 9.3)  = BCA  =  27.47°

 

So....in the smaller triangle BDC, angle BDC  is supplemental to angle BDA  =  180 - 78  = 102°

 

So  x  = angle DBC  =

 

180 - BDC - BCA  =

 

180  - 102 - 27.47  = 

 

50.53° =  50.5°

 

 

cool cool cool

CPhill  Apr 1, 2018

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