#1**0 **

30 – 2

You can get the side of the squares by using the Y-axis distances. ——— = 7

4

So __if__ the two squares in the middle were corner to corner

then the horizontal distance from A to B would be 4 • 7 = 28

__But__, by subtracting the X-axis distances,

the horizontal distance from A to B is only 27 – 3 = 24

So the third square up is displaced to the left by 28 – 24 = 4 units

So the X-axis component to **C** is 3 + 7 + 3 = 13

3 = the starting distance over from the Y-axis

7 = the length of the side of the bottom square

3 = how far **C** is from the top left corner of the second square up

And the Y-axis component to **C** is 2 + 7 + 7 = 16

2 = the starting distance up from the X-axis

7 = the length of the side of the bottom square

7 = the length of the side of the second square up

**C** is located at **(13,16)**

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Guest Nov 6, 2020