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# strugling on mathswatch

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https://vle.mathswatch.co.uk/images/questions/question19381.png

Nov 5, 2020

#1
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30 – 2

You can get the side of the squares by using the Y-axis distances.    ———   =  7

4

So if the two squares in the middle were corner to corner

then the horizontal distance from A to B would be 4 • 7 = 28

But, by subtracting the X-axis distances,

the horizontal distance from A to B is only 27 – 3 = 24

So the third square up is displaced to the left by 28 – 24 = 4 units

So the X-axis component to C is 3 + 7 + 3 = 13

3 = the starting distance over from the Y-axis

7 = the length of the side of the bottom square

3 = how far C is from the top left corner of the second square up

And the Y-axis component to C is 2 + 7 + 7 = 16

2 = the starting distance up from the X-axis

7 = the length of the side of the bottom square

7 = the length of the side of the second square up

C is located at (13,16)

Nov 6, 2020
#2
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Coordinates of C are (13, 16)

Nov 6, 2020