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https://vle.mathswatch.co.uk/images/questions/question19381.png

 Nov 5, 2020
 #1
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                                                                                                           30 – 2  

You can get the side of the squares by using the Y-axis distances.    ———   =  7  

                                                                                                                4  

So if the two squares in the middle were corner to corner  

then the horizontal distance from A to B would be 4 • 7 = 28  

 

But, by subtracting the X-axis distances,  

the horizontal distance from A to B is only 27 – 3 = 24  

 

So the third square up is displaced to the left by 28 – 24 = 4 units  

 

So the X-axis component to C is 3 + 7 + 3 = 13  

 

    3 = the starting distance over from the Y-axis  

    7 = the length of the side of the bottom square  

    3 = how far C is from the top left corner of the second square up  

 

And the Y-axis component to C is 2 + 7 + 7 = 16  

 

    2 = the starting distance up from the X-axis  

    7 = the length of the side of the bottom square  

    7 = the length of the side of the second square up  

 

                                              C is located at (13,16)  

 

 Nov 6, 2020
 #2
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Coordinates of C are (13, 16)

 

 Nov 6, 2020

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