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 Apr 11, 2018

Best Answer 

 #1
avatar+7616 
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Write   \(\frac{12}{\sqrt2}+\sqrt{18}\)   in the form   \(b\sqrt2\)   ,  where   \(b\)   is an integer.

 

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\(\ \quad\frac{12}{\sqrt2}+\sqrt{18}\\ =\\ \quad\frac{12}{\sqrt2}\cdot\frac{\sqrt2}{\sqrt2}+\sqrt{18}\\ =\\ \quad\frac{12\sqrt2}{2}+\sqrt{18}\\ =\\ \quad6\sqrt2+\sqrt{18}\\ =\\ \quad6\sqrt2+\sqrt{2\cdot3\cdot3}\\ =\\ \quad6\sqrt2+3\sqrt2\\ =\\ \quad9\sqrt2\)

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 Apr 11, 2018
 #1
avatar+7616 
+2
Best Answer

Write   \(\frac{12}{\sqrt2}+\sqrt{18}\)   in the form   \(b\sqrt2\)   ,  where   \(b\)   is an integer.

 

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\(\ \quad\frac{12}{\sqrt2}+\sqrt{18}\\ =\\ \quad\frac{12}{\sqrt2}\cdot\frac{\sqrt2}{\sqrt2}+\sqrt{18}\\ =\\ \quad\frac{12\sqrt2}{2}+\sqrt{18}\\ =\\ \quad6\sqrt2+\sqrt{18}\\ =\\ \quad6\sqrt2+\sqrt{2\cdot3\cdot3}\\ =\\ \quad6\sqrt2+3\sqrt2\\ =\\ \quad9\sqrt2\)

hectictar Apr 11, 2018

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