The formula M = log I/S determines the magnitude of an earthquake, where I is the intensity of the

earthquake and S is the intensity of a “standard earthquake.”

How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6?



Show your work



I felt like this is a lot easier then it looks but im having diffuclty. :/

Guest Nov 8, 2018

M = log (I/s)

10^m = I/s


10^m2 / 10^m1  =  I2/s  /  I1/s = I2/I1


I1  *  10^m2/ 10^m1  = I2          Let I1 and m1 refer to the magnitude 6

I1 * 10^8/10^6 = I2

I1 * 10^2 = I2

i1 * 100 = I2              this shows that I2  (magnitude 8) is 100 times the intensity I1 (magnitude 6)

ElectricPavlov  Nov 8, 2018

34 Online Users


New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.