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Consider the diagram below, with \(\angle ABC = \angle ACD = \angle DEA = 90^{\circ} \), as well as \(AB = 12, BC = 9, AD = 25\) and \(AE=24\):

 

 

What are \(\sin(\angle BAC), \sin(\angle BAD), \sin(\angle CAE),\)

in that order?

I got \(\angle BAC\), but im stuck on the other 2. Thank you in advance! smiley

 Jul 20, 2021
 #1
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sin BAC = 3/5, sin BAD = 15/16, sin CAE = 5/7.

 Jul 20, 2021
 #2
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Sorry, That is incorrect

elloooo  Jul 20, 2021
 #3
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Actually, I got it myself. Thank you guest for attempting to help! :)
I used sum of sines.

 Jul 20, 2021
 #4
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sin(∠BAC) = 3/5

sin(∠BAD) = 1

sin(∠CAE) = 0.936  ≈ 15/16

 

 Jul 20, 2021
edited by civonamzuk  Jul 20, 2021
 #5
avatar+1694 
+3

sin(∠CAE) = 0.936  = 117/125 smiley

civonamzuk  Jul 21, 2021

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