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# using 1,2,3,4 only once {operations (PEMDAS) and factorials allowed} how do you get -100 and 12.75?

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using 1,2,3,4 only once {operations (PEMDAS) and factorials allowed} how do you get -100 and 12.75?

Nov 2, 2015

#2
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-[(1 X 2) -(3 X 4)]^2

- [2 - 12]^2

-[-10^2]=-100

12 + 3/4=12.75

Nov 2, 2015

#1
+3

[(3x4)-(1x2)]2

or just

(3x4-1x2)2

Nov 2, 2015
#2
+3

-[(1 X 2) -(3 X 4)]^2

- [2 - 12]^2

-[-10^2]=-100

12 + 3/4=12.75

Guest Nov 2, 2015
#3
+3

Hi Guest,    You used the 2 twice in both you answers. I can 'fudge' too.   LOL

using 1,2,3,4 only once {operations (PEMDAS) and factorials allowed} how do you get -100 and 12.75?

1)        (2+3)1 / 4   =   51  /  4   =   12.75       LOL Here is another 'fudge' one

2)         (12)+3/4      = 12  3/4

HERE IS A REAL ONE!!

3)      (3!+4)^2  =100      If I haver to use the 1 as well I can just multiply the whole lot by 1.   Nov 2, 2015
edited by Melody  Nov 2, 2015
edited by Melody  Nov 2, 2015
#4
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I don't think this one really is answered yet !!

Most of those answers look a bit 'fudged' to me.       lol Nov 2, 2015
#5
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(3! + 4)^2 X -1= -100

12 + 3/4=12.75

Nov 2, 2015