We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
1
919
5
avatar

using 1,2,3,4 only once {operations (PEMDAS) and factorials allowed} how do you get -100 and 12.75?

 Nov 2, 2015

Best Answer 

 #2
avatar
+3

  -[(1 X 2) -(3 X 4)]^2

  - [2 - 12]^2

  -[-10^2]=-100

 

12 + 3/4=12.75

 Nov 2, 2015
 #1
avatar
+3

[(3x4)-(1x2)]2

or just

(3x4-1x2)2

 Nov 2, 2015
 #2
avatar
+3
Best Answer

  -[(1 X 2) -(3 X 4)]^2

  - [2 - 12]^2

  -[-10^2]=-100

 

12 + 3/4=12.75

Guest Nov 2, 2015
 #3
avatar+105509 
+3

 

Hi Guest,    You used the 2 twice in both you answers.     frown

 

 

I can 'fudge' too.   LOL

 

using 1,2,3,4 only once {operations (PEMDAS) and factorials allowed} how do you get -100 and 12.75?

 

1)        (2+3)1 / 4   =   51  /  4   =   12.75       LOL    cheeky

 

Here is another 'fudge' one

 

2)         (12)+3/4      = 12  3/4

 

HERE IS A REAL ONE!!

 

3)      (3!+4)^2  =100      If I haver to use the 1 as well I can just multiply the whole lot by 1.   cheekylaughwink

 Nov 2, 2015
edited by Melody  Nov 2, 2015
edited by Melody  Nov 2, 2015
 #4
avatar+105509 
0

I don't think this one really is answered yet !!

 

Most of those answers look a bit 'fudged' to me.       lol      indecision

 Nov 2, 2015
 #5
avatar
0

(3! + 4)^2 X -1= -100

12 + 3/4=12.75

 Nov 2, 2015

23 Online Users

avatar
avatar