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Which graph represents  f(x)=−12x2 ?

AngelRay  Feb 7, 2018

Best Answer 

 #1
avatar+6953 
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f(x)   =   -\(\frac12\)x2

 

f(0)   =   -\(\frac12\)(0)2   =   -\(\frac12\)(0)   =   0          So the graph of  f(x)  passes through the point  (0, 0) .

 

f(1)   =   -\(\frac12\)(1)2   =   -\(\frac12\)(1)   =   -\(\frac12\)        So the graph of  f(x)  passes through the point  (1, -\(\frac12\)) .

 

f(-1)   =   -\(\frac12\)(-1)2   =   -\(\frac12\)(1)   =   -\(\frac12\)     So the graph of  f(x)  passes through the point  (-1, -\(\frac12\)) .

 

The graph of  f(x)  passes through the points  (0, 0) ,  (1, -\(\frac12\)) ,  and  (-1, -\(\frac12\)) .

 

Only one of the graphs in the options passes through these points.

hectictar  Feb 8, 2018
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1+0 Answers

 #1
avatar+6953 
+2
Best Answer

f(x)   =   -\(\frac12\)x2

 

f(0)   =   -\(\frac12\)(0)2   =   -\(\frac12\)(0)   =   0          So the graph of  f(x)  passes through the point  (0, 0) .

 

f(1)   =   -\(\frac12\)(1)2   =   -\(\frac12\)(1)   =   -\(\frac12\)        So the graph of  f(x)  passes through the point  (1, -\(\frac12\)) .

 

f(-1)   =   -\(\frac12\)(-1)2   =   -\(\frac12\)(1)   =   -\(\frac12\)     So the graph of  f(x)  passes through the point  (-1, -\(\frac12\)) .

 

The graph of  f(x)  passes through the points  (0, 0) ,  (1, -\(\frac12\)) ,  and  (-1, -\(\frac12\)) .

 

Only one of the graphs in the options passes through these points.

hectictar  Feb 8, 2018

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